25x^2-50x-26=0

Solution for 25x^2-50x-26=0 equation:

25x^2-50x-26=0

a = 25; b = -50; c = -26;
Δ = b2-4ac
Δ = -502-4·25·(-26)
Δ = 5100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5100}=\sqrt{100*51}=\sqrt{100}*\sqrt{51}=10\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-10\sqrt{51}}{2*25}=\frac{50-10\sqrt{51}}{50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+10\sqrt{51}}{2*25}=\frac{50+10\sqrt{51}}{50}
$